Complete algebra guide • Step-by-step solutions
\( a_n = a_1 \times r^{n-1} \)
This formula calculates the n-th term of a geometric sequence, where:
The sum of first n terms is given by: \( S_n = a_1 \frac{1-r^n}{1-r} \) (when r ≠ 1) or \( S_n = na_1 \) (when r = 1)
Geometric sequences have a constant ratio between consecutive terms, forming an exponential pattern. They appear in many real-world scenarios like population growth, compound interest, and radioactive decay.
| Term | Position (n) | Value | Formula |
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Enter parameters to see solution steps.
A geometric sequence is a sequence of numbers where each term after the first is obtained by multiplying the previous term by a constant value (called the common ratio). The sequence has the general form: a₁, a₁r, a₁r², a₁r³, ..., a₁r^(n-1), where a₁ is the first term and r is the common ratio. Geometric sequences represent exponential growth or decay patterns.
The general term of a geometric sequence is given by:
Where:
Key characteristics of geometric sequences:
In the geometric sequence 2, 6, 18, 54, 162, ..., what is the common ratio?
In a geometric sequence, the common ratio (r) is the constant value that multiplies each term to get the next term.
We can find r by dividing any term by the previous term:
r = 6 ÷ 2 = 3
Or: r = 18 ÷ 6 = 3
Or: r = 54 ÷ 18 = 3
Therefore, the common ratio is 3. The answer is B) 3.
The common ratio is fundamental to understanding geometric sequences. It's the constant multiplier between consecutive terms. Once you know the first term and the common ratio, you can generate any term in the sequence using the formula aₙ = a₁ × r^(n-1). The common ratio also determines whether the sequence grows exponentially (|r| > 1), decays exponentially (|r| < 1), or remains constant (r = 1).
Geometric Sequence: A sequence where each term is multiplied by the same constant to get the next term
Common Ratio: The constant value that multiplies each term to get the next term
Term: Each individual number in the sequence
• r = aₙ₊₁ ÷ aₙ (ratio between consecutive terms)
• All ratios between consecutive terms are equal
• If |r| > 1, sequence grows; if |r| < 1, sequence decays
• Divide any term by the previous term to find r
• Verify by checking multiple consecutive pairs
• The sequence grows if |r| > 1, decays if |r| < 1
• Dividing the wrong way (aₙ ÷ aₙ₊₁ instead of aₙ₊₁ ÷ aₙ)
• Forgetting to check that the ratio is constant throughout
• Confusing with arithmetic sequences (additive instead of multiplicative)
Find the 8th term of the geometric sequence where the first term is 5 and the common ratio is 2. Show your work.
Using the geometric sequence formula: aₙ = a₁ × r^(n-1)
Given: a₁ = 5, r = 2, n = 8
Step 1: Substitute values into the formula:
a₈ = 5 × 2^(8-1)
Step 2: Simplify the exponent:
a₈ = 5 × 2^7
Step 3: Calculate 2^7:
2^7 = 128
Step 4: Multiply:
a₈ = 5 × 128 = 640
Therefore, the 8th term is 640.
The formula aₙ = a₁ × r^(n-1) is derived from the concept that to get from the first term to the nth term, we need to multiply by the common ratio (n-1) times. For example, to get from a₁ to a₂, we multiply by r once; to get from a₁ to a₃, we multiply by r twice, and so on. The formula allows us to find any term directly without calculating all the preceding terms.
n-th Term: The term at position n in the sequence
Explicit Formula: A formula that calculates any term directly
Exponential Function: A function where the variable is in the exponent
• aₙ = a₁ × r^(n-1) (explicit formula)
• To get from a₁ to aₙ, multiply by r exactly (n-1) times
• Always verify by calculating a few terms manually
• Remember: (n-1) is the number of times you multiply by r
• Always double-check by calculating a few terms
• The formula works for any position n in the sequence
• Using n instead of (n-1) in the exponent
• Arithmetic errors in exponentiation
• Forgetting the order of operations when evaluating powers
A bacteria culture starts with 100 bacteria and triples in size every hour. How many bacteria will be present after 6 hours? How many bacteria were present after 3 hours?
This is a geometric sequence problem where: a₁ = 100 (initial bacteria count) r = 3 (triples each hour) n = 7 (for after 6 hours, since we start counting from hour 0)
Step 1: Find bacteria after 6 hours using aₙ = a₁ × r^(n-1): After 6 hours corresponds to the 7th term (hour 0, 1, 2, 3, 4, 5, 6):
a₇ = 100 × 3^(7-1) = 100 × 3^6 = 100 × 729 = 72,900 bacteria
Step 2: Find bacteria after 3 hours (4th term):
a₄ = 100 × 3^(4-1) = 100 × 3^3 = 100 × 27 = 2,700 bacteria
Therefore, there will be 72,900 bacteria after 6 hours and 2,700 bacteria after 3 hours.
This problem demonstrates how geometric sequences model exponential growth in real-world situations. The bacterial growth forms a geometric sequence because each hour the population multiplies by the same factor (3). This creates an exponential pattern of growth. The key is identifying that the starting amount is a₁ and the growth factor is r.
Exponential Growth: Growth that increases by a constant factor
Real-World Application: Using math to solve practical problemsCompound Growth: Growth that builds upon itself
• aₙ = a₁ × r^(n-1) (for geometric sequences)
• Time periods often correspond to term positions
• Always identify a₁, r, and n before applying formulas
• Look for "multiplies by" or "increases by a factor" to identify geometric sequences
• Pay attention to whether the starting value is at n=0 or n=1
• Verify by calculating first few terms manually
• Miscounting the term number for time periods
• Forgetting to evaluate large exponents correctly
• Misidentifying the common ratio in word problems
In a geometric sequence, the 3rd term is 12 and the 6th term is 96. Find the first term and the common ratio. Then find the 10th term.
Using the formula aₙ = a₁ × r^(n-1), we can set up equations:
For the 3rd term: a₃ = a₁ × r² = 12
For the 6th term: a₆ = a₁ × r⁵ = 96
Step 1: Divide the second equation by the first to eliminate a₁:
(a₁ × r⁵) ÷ (a₁ × r²) = 96 ÷ 12
r³ = 8
r = 2
Step 2: Substitute r = 2 into the first equation:
a₁ × 2² = 12
a₁ × 4 = 12
a₁ = 3
Step 3: Find the 10th term:
a₁₀ = 3 × 2^(10-1) = 3 × 2⁹ = 3 × 512 = 1,536
Therefore, a₁ = 3, r = 2, and the 10th term is 1,536.
When given two terms of a geometric sequence, we can set up a system of equations to find both the first term and common ratio. This is because we have two unknowns (a₁ and r) and two pieces of information. The key insight is that the ratio of any two terms equals the common ratio raised to the power of the difference in their positions.
System of Equations: Multiple equations with the same unknowns
Simultaneous Equations: Equations solved together
Division Property: Dividing terms eliminates the first term
• If aₘ and aₙ are known, then aₙ/aₘ = r^(n-m)
• Two terms allow solving for both a₁ and r
• Always verify by checking that the found values work
• Use division to eliminate a₁ when solving systems
• Verify by calculating the known terms with your answers
• The ratio between terms equals r raised to the difference in positions
• Setting up incorrect equations based on the formula
• Making exponent errors when dividing terms
• Forgetting to verify the final answer
What is the sum of the first 5 terms of the geometric sequence 3, 6, 12, 24, ...?
First, identify the parameters of the sequence:
a₁ = 3 (first term)
r = 6 ÷ 3 = 2 (common ratio)
n = 5 (number of terms)
Using the sum formula for geometric series: Sₙ = a₁(rⁿ - 1)/(r - 1)
S₅ = 3(2⁵ - 1)/(2 - 1)
S₅ = 3(32 - 1)/1
S₅ = 3(31) = 93
Verification by direct calculation: 3 + 6 + 12 + 24 + 48 = 93
Therefore, the sum of the first 5 terms is 93. The answer is A) 93.
When calculating the sum of a geometric series, we use the formula Sₙ = a₁(rⁿ - 1)/(r - 1) when r ≠ 1. This formula is much more efficient than adding each term individually, especially for large n. The formula comes from the algebraic manipulation of the series and the properties of geometric progressions.
Geometric Series: The sum of the terms of a geometric sequence
Partial Sum: The sum of the first n terms
Finite Series: A sum with a limited number of terms
• Sₙ = a₁(rⁿ - 1)/(r - 1) when r ≠ 1
• Sₙ = na₁ when r = 1
• Always verify with direct calculation for small n
• Use the formula that requires fewer calculations
• Always double-check your arithmetic
• The formula becomes undefined when r = 1, requiring special handling
• Forgetting to check if r = 1 requires a different formula
• Making arithmetic errors with large exponents
• Confusing rⁿ - 1 with (r - 1)ⁿ in the formula
aₙ = a₁ × r^(n-1), where a₁ is the first term and r is the common ratio.
\(S_n = a_1 \frac{r^n - 1}{r - 1}\) (when r ≠ 1) or \(S_n = na_1\) (when r = 1)
Where Sₙ = sum of first n terms, a₁ = first term, r = common ratio.
Exponential growth patterns, compound interest, population models, radioactive decay.
Q: What's the difference between a geometric sequence and an arithmetic sequence?
A: The key difference lies in how the terms progress:
Geometric Sequence: Each term is found by multiplying the previous term by a constant value (common ratio). For example: 2, 6, 18, 54, 162... (multiply by 3 each time).
Arithmetic Sequence: Each term is found by adding a constant value (common difference) to the previous term. For example: 2, 5, 8, 11, 14... (add 3 each time).
Geometric sequences grow exponentially while arithmetic sequences grow linearly. The general term for a geometric sequence is aₙ = a₁ × r^(n-1), while for an arithmetic sequence it's aₙ = a₁ + (n-1)d.
Q: Can geometric sequences have negative common ratios?
A: Yes, geometric sequences can have negative common ratios. When r < 0, the sequence alternates in sign. For example, in the sequence 2, -6, 18, -54, 162..., the common ratio is -3. Each term is -3 times the previous term.
Negative common ratios create oscillating sequences that alternate between positive and negative values. These are useful in modeling alternating current in electrical engineering, economic cycles with alternating growth and decline, and other phenomena that exhibit periodic reversals. The geometric sequence formula works identically with negative ratios: aₙ = a₁ × r^(n-1).